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A Recurrence Relational Expression of Integral and Application
Author(s): 
Pages: 25-27
Year: Issue:  3
Journal: Journal of Yueyang Normal University

Keyword:  不定积分 递推 应用 推广;
Abstract: 得到了积分In=∫(1/((xm+c)n))dx(n,m∈R,且(n-1)m≠1,cmn≠0) 的递推公式In=1/c·[1-(1/((n-1)m))]I(n-1)+(1/(c(n-1)m))·(x/((xm+c)(n-1)))·并举例给出了应用.
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